F(x)=2x^2-2x+5

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Solution for F(x)=2x^2-2x+5 equation: 



(F)=2F^2-2F+5

We move all terms to the left:

(F)-(2F^2-2F+5)=0

We get rid of parentheses

-2F^2+F+2F-5=0

We add all the numbers together, and all the variables

-2F^2+3F-5=0

a = -2; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-2)·(-5)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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